Number Series Questions PDF

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Reasoning Missing Number Series pdf

Today we shear Number Series Questions PDF Reasoning Missing Number Series pdf In Reasoning Ability section Number Series is most important topic for the Reasoning Ability Section. so u can also download pdf.

1. 17, 22, 27, 32, …… ? …….

(A) 33    (B) 35    (C) 38    (D) 37

2. 87, 74, 61, 48, …… ? …….

(A) 35    (B) 30    (C) 32     (D) 25

3. 135, 106, 77, …… ? …….,19.

(A) 40    (B) 45    (C) 48     (D) 35

4. 25, 75, 35, 70, 45, …… ? …….

(A) 65    (B) 60     (C) 55     (D) 85

5. 82, 25, 74, 40, 60, …… ? ……..

(A) 65    (B) 55    (C) 60     (D) 72

6. 15, 45, 135, 405, …… ? …….

(A) 550    (B) 650    (C) 945    (D) 1215

7. 3, 7, 15, 31, 61, …… ? …….

(A) 125    (B) 112    (C) 127     (D) 118

8. 5, 12, 26, 54, 110, …… ? ……..

(A) 220    (B) 222    (C) 210     (D) 156

9. 198, 194, 185, 169,…… ? …….

(A) 144    (B) 128     (C) 96      (D) 116

10. 13, 35, 57, 79, 911, …… ? …….

(A) 1110    (B) 1112    (C) 1113    (D) 1315

11. 8, 13, 13, 23, 18, 33, …… ? …….

(A) 23    (B) 21     (C) 31    (D) 35

12. 4, 9, 16, 16, 25, …… ? ……..

(A) 42     (B) 49     (C) 38     (D) 52

Explanation

1. Each number increases by 5.
2. Each number decreases by 13.
3. Each number decreases by 35.
4. There are two patterns following in this question in first pattern 10 is added in each numbers (25, 35, 45) and in second pattern 5 is subtract from each number (75, 70, 65).
5. There are two patterns following in this question in first pattern 8 is subtracted from each numbers (82, 74, 66) and in second pattern 15 is added in eachnumber.
6. Each number is multiplied by 3.
7. Each number in the series is one more than twice the preceding number. (7 = (3×2+1), 15 = (7×2+1), 31 = (15×2+1), 63 = (31×2+1), 127= (63×2+1))
8. Each number in the series is 2 more than twice the preceding number. (12 = (5×2+2), 26 = (12×2+2), 54 = (26×2+2), 110 = (54×2+2), 222 = (110×2+2))
9. The pattern is -2 2 , -3 2 , -4 2 , -5 2 .
10. The pattern is , +32 , +42 , +5 2 , +62 .
11. The terms of the given series are number formed by joining together consecutive odd number in order. 1 and 3, 3 and 5, 5 and 7, 7 and 9, 9 and 11, so missing term is 11 and 13 =1113
12. There are two patterns following in this question. In first pattern 5 is added in each number at every old place (8, 13, 18, 23). In second pattern 10 is added at every even places (13, 23,33)

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